Process scan, to try and see what each of process is generating, and which should B and S really be.

SM processes (background)

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g g > t t~ t t~ and g g > t t~ all, all > t t~ [QED,QCD default]

72 diagrams in the first case, with only gluons as intermediate particles. σ = 8.33 fb

17 diagrams in the second case. "all" is only gluons, so we're generating g g > t t~ g, (g > t t~) σ = 25.14 fb

process	g g > t t~ t t~	g g > t t~ all, all > t t~
	yes	yes
	yes	yes
	yes	no
	yes	yes
	yes	yes
	yes	yes
	yes	yes
	yes	yes

It seems there is only one type of diagram (11) that is not present in g g > t t~ all, (all > t t~). However, in this case

there are way less "permutations" (why?)

g g > t t~ t t~ and g g > t t~ all, all > t t~ [QED = 99 ,QCD=99]

216 diagrams in the first case. Gluons, Z, photon and Higgs as intermidiates. Number of diagrams ~x4 with respect to default orders

16+8+8+8 diagrams in the second case. Now "all" is either g, z, a or h. So, g g > t t~ {a,z,h,g}, ({a,z,h,g} > t t~)

The diagram distribution is going to be similar to that in the table above, with Z, photons and higgs entering the processes now.

From this it seems that all the processes in g g > t t~ all, all > t t~ are contained in g g > t t~ t t~. Generating the latter should contain the former, so there is no need of adding both.

-- AlbertoGasconBravo - 2015-03-24