$\int_{-\infty}^\infty e^{ -\alpha x^2 } dx = \sqrt{ \frac{\pi}{\alpha} }$ -- Main.ssuvorov - 2019-12-09
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PDFpdf TPC_DESY_05_12.pdf r1 manage 2752.7 K 2019-12-09 - 14:17 SergeySuvorov  
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Topic revision: r1 - 2019-12-09 - SergeySuvorov
 
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