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When $a \ne 0$, there are two solutions to \(ax^2 + bx + c = 0\) and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$

In a heading $B_s$

In a table

$B_s$ yields	xyz

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When , there are two solutions to and they are

In a heading

In a table

yields	xyz

--++ Tests

• Set H=\mathrm{H}
• Set HZZ = $\mathrm{H}\rightarrow ZZ$

$\mathrm{H}\rightarrow ZZ$

$$\mathrm{H}\rightarrow ZZ$ \pm%